[spectra]

Originally Posted by MVPgoes2nash

so ur sayin 5/6 would be 5 divided by 6 or 500 divided by 6

then i get the answer

ok think about it this way

you have a fraction

(n is any number in the numerator)
(b is any number in the denominator)

n/b

if 10<b<100, find what number x b = 100

example

5/6


find what number x 6 is equal to 100
(y = variable)
6y = 100
y = 100/6

ok so 6(100/6) = 100

now you multiply BOTH the numerator and denominator by 5/3

so you have

5(100/6) / 6(100/6)

500/6 / 100
250/3 / 100

now do 250/3.
250/3 = 83.33333333333333333333333...
now do 83.333333333333333... / 100

you get 0.8333333333333...

[MVPgoes2nash]

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[event_staff_9]

yeah i think the others did a great job explaining it to you; i dont know how to explain it lol but yeah thats it!

[spectra]

i'm sorry but if you still don't get it you need help (serious help)

also if all else fails use a calculator

[LEFTY15]

can you guys help me out with this? i need to find the limit...


lim ......... x cos(-2x + 1)
x -> 0.........x^2 + x



(as x goes to 0)
let me know if you need me to better explain the equation. thanks in advance


oh and if it helps, the answer is cos(1). i just need to know HOW to do it. thanks

[spectra]

well you first plug in x for zero

you get 0/0

so it means you have to simplify it

lim xcos(-2x+1)
x-> 0 X^2 + x

goes to

cos(-2x+1)/(x+1)

well if you plug in zero now

cos(1)/1

lim x->0 = cos(1)

[event_staff_9]

yeah sorry, i was in New York yesterday and today but spectra's got your back

also, im a big rush but im pretty sure you can L'Hopital it but we can look into it later and might be too time consuming

[spectra]

yes L'hopital can be used

xcos(-2x+1)/(x^2 + x)

because the substitution of 0 for x yields 0/0 or infinity/infinity

you take the derivative of the top and bottom
top: cos(-2x+1) + xsin(-2x+1)(2)

bottom
2x+1

so you have cos(-2x+1) + 2xsin(-2x+1) / 2x+1

then plug in zero

cos(1) + 0 / 1

=cos(1)

the normal simplification is easier here though

[event_staff_9]

Originally Posted by spectra

yes L'hopital can be used

xcos(-2x+1)/(x^2 + x)

because the substitution of 0 for x yields 0/0 or infinity/infinity

you take the derivative of the top and bottom
top: cos(-2x+1) + xsin(-2x+1)(2)

bottom
2x+1

so you have cos(-2x+1) + 2xsin(-2x+1) / 2x+1

then plug in zero

cos(1) + 0 / 1

=cos(1)

the normal simplification is easier here though

yeah i figured it would work; thanks for showing it out, i was in a rush yesterday, and yes it is easier simplifying as i said i just was in. :D:D:D

awesome to see people asking and multiple people helping out :)

[spectra]

ha by multiple people you mean me

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